Two spaceships A and B approach Earth in the same direction. As measured from ship A, Earth is approaching at 0.5 c and ship B at 0.25 c. Both ships reach Earth at the same time. For this scenario to hold, from Earth's frame of reference, ship A must be approaching twice as fast as ship B. With Newtonian physics, this holds true. With Einstein's special relativity however we have:
vBE = c(0.5 - 0.25) / (1 + 0.5*0.25) = 0.22 c
Where vBE is relativistic velocity of ship B as measured from Earth. And since vAE, the relativistic velocity of ship A as measured from Earth, is 0.5 c, it is different than twice the velocity of ship B measued from Earth which is 0.44 c. No acceleration or deceleration in the scenario.
This means that Einstein's special relativity is incorrect. Even with any kind of distance contraction/expansion, Einstein's special relativity is still incorrect, since:
In this other scenario, a single spaceship approaches Earth at 0.4 c and passes by close to the moon. When the spaceship passes the moon, the distance from Earth to the spaceship is measured with Earth as the reference frame. According to Newtonian physics, the distance from Earth to both the spaceship and the moon is the same. With Einstein's special relativity, either that too is the case, and then the first scenario invalidates Einstein's special relativity, or some form of contraction/expansion equation of the distance from Earth to the spaceship is used, and then Einstein's special relativity is invalidated since both the spaceship and the moon occupy the same position in space at the time of the measurement and therefore the distance from that point should be the same.
vBE = c(0.5 - 0.25) / (1 + 0.5*0.25) = 0.22 c
Where vBE is relativistic velocity of ship B as measured from Earth. And since vAE, the relativistic velocity of ship A as measured from Earth, is 0.5 c, it is different than twice the velocity of ship B measued from Earth which is 0.44 c. No acceleration or deceleration in the scenario.
This means that Einstein's special relativity is incorrect. Even with any kind of distance contraction/expansion, Einstein's special relativity is still incorrect, since:
In this other scenario, a single spaceship approaches Earth at 0.4 c and passes by close to the moon. When the spaceship passes the moon, the distance from Earth to the spaceship is measured with Earth as the reference frame. According to Newtonian physics, the distance from Earth to both the spaceship and the moon is the same. With Einstein's special relativity, either that too is the case, and then the first scenario invalidates Einstein's special relativity, or some form of contraction/expansion equation of the distance from Earth to the spaceship is used, and then Einstein's special relativity is invalidated since both the spaceship and the moon occupy the same position in space at the time of the measurement and therefore the distance from that point should be the same.
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