In the classic Light Clock Thought Experiment the clock is shown standing perpendicular (at a right angle) to the plane of the clock’s travel. What however if the same clock was tilted forward at an angle (say 45 degrees) as shown in the image below?
The light “blip” (red line) reflected from the top mirror of position 1 strikes the bottom mirror of position 2 at a particular angle of incidence (AOI). The Law Of Reflection dictates that the blip is reflected from the mirror at an equal and opposite angle of relection (AOR) as indicated by the dotted line. For the blip to reach and be refected from the top mirror at position 3 however, it has to be refelected at a completely different angle (AO?).
Also the distance the blip travels from the top mirror of position 1 to the bottom mirror of position 2 is considerably shorter than the distance it travels from the bottom mirror of position 2 to the top mirror of position 3 (in the same time).
Seems this light clock would have to break both the Law of Reflection and the constant speed of c. How can this be so?
The light “blip” (red line) reflected from the top mirror of position 1 strikes the bottom mirror of position 2 at a particular angle of incidence (AOI). The Law Of Reflection dictates that the blip is reflected from the mirror at an equal and opposite angle of relection (AOR) as indicated by the dotted line. For the blip to reach and be refected from the top mirror at position 3 however, it has to be refelected at a completely different angle (AO?).
Also the distance the blip travels from the top mirror of position 1 to the bottom mirror of position 2 is considerably shorter than the distance it travels from the bottom mirror of position 2 to the top mirror of position 3 (in the same time).
Seems this light clock would have to break both the Law of Reflection and the constant speed of c. How can this be so?
via International Skeptics Forum http://ift.tt/2swHrFL
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